Assignment1 – BD309_2526 – Steven Harazaki Lase – 2381477560

PERTANYAAN :

1.A law firm seeks to recruit top-quality experienced lawyers. The total package offered is

the sum of three separate components: a basic salary which is 1.2 times the candidate’s

current salary together with an additional $3000 for each year worked as a qualified

lawyer and an extra $1000 for every year that they are over the age of 21.

Work out a formula that could be used to calculate the total salary, S, offered to

someone who is A years of age, has E years of relevant experience and who currently

earns $N. Hence work out the salary offered to someone who is 30 years old with five

years’ experience and who currently earns $150 000.

 

2.Write down a formula for each situation:

a. A plumber has a fixed call-out charge of $80 and has an hourly rate of $60. Work

out the total charge, C, for a job that takes L hours in which the cost of materials

and parts is $K.

b.An airport currency exchange booth charges a fixed fee of $10 on all transactions

and offers  an exchange rate of 1 dollar to 0.8 euros. Work out the total charge, C,

(in $) for buying x euros.

c. A firm provides 5 hours of in-house training for each of its semi-skilled workers and

10 hours of training for each of its skilled workers. Work out the total number of

hours, H, if the firm employs a semi-skilled and b skilled workers.

d. A car hire company charges $C a day together with an additional $c per mile. Work

out the total charge, $X, for hiring a car for d days and travelling m miles during

that time.

Without using a calculator, evaluate

(a) 10 × (−2) (b) (−1) × (−3) (c) (−8) ÷ 2 (d) (−5) ÷ (−5)

(e) 24 ÷ (−2) (f) (−10) × (−5) (f) (−6) × 5 × (−1)

 

3.Without using a calculator, evaluate

(a) 5 − 6 (b) −1 − 2 (c) 6 − 17 (d) −7 + 23

(e) −7 − (−6) (f) −4 − 9 (g) 7 − (−4) (h) −9 − (−9)

(i) 12 − 43 ( j) 2 + 6 − 10

 

4.Without using a calculator, evaluate

(a) 5 × 2 − 13 (b) 5 × (1 − 4)

(c) 1 − 6 × 7 (d) −5 + 6 ÷ 3 (e) 2 × (−3)2 (f) −10 + 22

(g) (−2)2 − 5 × 6 + 1 ( j)

 

5.Simplify each of the following algebraic expressions:

(a) 2 × P × Q (b) I × 8 (c) 3 × x × y

(d) 4 × q × w × z (e) b × b (f) k × 3 × k

 

STATUS :

KETERANGAN :

BUKTI :

1.

Step 1: Define the formula

We are told:

  • Basic salary = 1.2×N1.2 \times N

  • Experience bonus = 3000×E3000 \times E

  • Age bonus = 1000×(A−21)1000 \times (A – 21) (only counts years over age 21)

So, the total salary SS is:

S=1.2N+3000E+1000(A−21)S = 1.2N + 3000E + 1000(A – 21)

Step 2: Substitute the values given

  • A=30A = 30

  • E=5E = 5

  • N=150,000N = 150,000

S=1.2(150,000)+3000(5)+1000(30−21)S = 1.2(150,000) + 3000(5) + 1000(30 – 21)

Step 3: Calculate step by step

  1. Basic salary:

1.2×150,000=180,0001.2 \times 150,000 = 180,000

  1. Experience bonus:

3000×5=15,0003000 \times 5 = 15,000

  1. Age bonus:

30−21=9⇒1000×9=9,00030 – 21 = 9 \quad \Rightarrow \quad 1000 \times 9 = 9,000

Step 4: Add them up

S=180,000+15,000+9,000=204,000S = 180,000 + 15,000 + 9,000 = 204,000

Final Formula:

S=1.2N+3000E+1000(A−21)\boxed{S = 1.2N + 3000E + 1000(A – 21)}

Salary Offered:

S=$204,000\boxed{S = \$204,000}

 

(a) Plumber: fixed call-out $80, hourly rate $60, job takes LL hours, materials cost $KK.

C=80+60L+K\boxed{C = 80 + 60L + K}

(b) Currency booth: fixed fee $10, exchange rate 1$ =0.8 euros1\$\ = 0.8\ \text{euros}. To buy xx euros you need x0.8=1.25x\dfrac{x}{0.8}=1.25x dollars plus the fee:

C=10+x0.8=10+1.25x\boxed{C = 10 + \dfrac{x}{0.8} = 10 + 1.25x}

(c) Training hours: 5 hours per semi-skilled worker, 10 hours per skilled worker. If firm employs aa semi-skilled and bb skilled workers:

H=5a+10b\boxed{H = 5a + 10b}

(d) Car hire: $CC per day and $cc per mile. For dd days and mm miles:

X=Cd+cm\boxed{X = Cd + cm}

Without calculator — evaluate:

Work carefully, step by step:

(a) 10×(−2)=−2010 \times (-2) = -20
(b) (−1)×(−3)=+3(-1)\times(-3)=+3
(c) (−8)÷2=−4(-8)\div 2 = -4
(d) (−5)÷(−5)=+1(-5)\div(-5)=+1
(e) 24÷(−2)=−1224\div(-2) = -12
(f) (−10)×(−5)=+50(-10)\times(-5)=+50

You listed (f) twice; I’ll label the last one as (g):

(g) (−6)×5×(−1)(-6)\times 5 \times (-1). First (−6)×5=−30(-6)\times 5=-30, then −30×(−1)=+30-30\times(-1)=+30.

So final results:
(a) −20-20, (b) 33, (c) −4-4, (d) 11, (e) −12-12, (f) 5050, (g) 3030

3.

(a) 5−6=−15 – 6 = -1

(b) −1−2=−3-1 – 2 = -3

(c) 6−17=−116 – 17 = -11

(d) −7+23=16-7 + 23 = 16

(e) −7−(−6)=−7+6=−1-7 – (-6) = -7 + 6 = -1

(f) −4−9=−13-4 – 9 = -13

(g) 7−(−4)=7+4=117 – (-4) = 7 + 4 = 11

(h) −9−(−9)=−9+9=0-9 – (-9) = -9 + 9 = 0

(i) 12−43=−3112 – 43 = -31

(j) 2+6−10=8−10=−22 + 6 – 10 = 8 – 10 = -2

4.

(a) 5 × 2 − 13

  1. 5×2=105 × 2 = 10

  2. 10−13=−310 − 13 = -3
    Jawaban: -3

(b) 5 × (1 − 4)

  1. Hitung dalam kurung: 1−4=−31 − 4 = -3

  2. 5×−3=−155 × -3 = -15
    Jawaban: -15

(c) 1 − 6 × 7

  1. Kali dulu: 6×7=426 × 7 = 42

  2. 1−42=−411 − 42 = -41
    Jawaban: -41

(d) −5 + 6 ÷ 3

  1. Bagi dulu: 6÷3=26 ÷ 3 = 2

  2. −5+2=−3−5 + 2 = -3
    Jawaban: -3

(e) 2 × (−3)²

  1. Kuadrat dulu: (−3)2=9(−3)² = 9

  2. 2×9=182 × 9 = 18
    Jawaban: 18

(f) −10 + 22
−10+22=12-10 + 22 = 12
Jawaban: 12

(g) (−2)² − 5 × 6 + 1

  1. Kuadrat dulu: (−2)2=4(−2)² = 4

  2. Kali: 5×6=305 × 6 = 30

  3. 4−30+1=(4+1)−30=5−30=−254 − 30 + 1 = (4 + 1) − 30 = 5 − 30 = -25
    Jawaban: -25

 

5.

(a) 2 × P × Q
Tidak ada angka atau variabel yang sama untuk dikalikan, jadi kita cukup menuliskannya berurutan:
Jawaban: 2PQ

(b) I × 8
Urutkan angka di depan huruf:
Jawaban: 8I

(c) 3 × x × y
Gabungkan:
Jawaban: 3xy

(d) 4 × q × w × z
Gabungkan:
Jawaban: 4qwz

(e) b × b
Variabel sama → dijadikan pangkat:
Jawaban:

(f) k × 3 × k

  1. Gabungkan angka dulu: 33

  2. k×k=k2k × k = k²
    Jawaban: 3k²

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